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4c7a1a4
initial: ex.1,2
parfenovma 0d1fd62
full cw
parfenovma 4f80257
additional excercises
parfenovma bfecb72
fix ordering
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add code in matlab
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fix russian monofont in code
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add newpages
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format
parfenovma 74cde69
add errors + refactoring
parfenovma 0fa8c7a
add errors + refactoring
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add errors + refactoring
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styling
parfenovma 7c8d259
fixes
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removed formulae numeration
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add presentation
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add presentation
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add presentation
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add presentation
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add presentation
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| Original file line number | Diff line number | Diff line change |
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| @@ -0,0 +1,35 @@ | ||
| name: Build Marp Presentations (PDF) | ||
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| on: | ||
| push: | ||
| branches: [ "main", "master" ] | ||
| paths: | ||
| - 'slides/**.md' | ||
| workflow_dispatch: | ||
|
|
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| jobs: | ||
| build: | ||
| runs-on: ubuntu-latest | ||
|
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| steps: | ||
| - name: checkout | ||
| uses: actions/checkout@v4 | ||
|
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| - name: install node | ||
| uses: actions/setup-node@v4 | ||
| with: | ||
| node-version: '20' | ||
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| - name: generate with marp | ||
| run: | | ||
| npx @marp-team/marp-cli@latest slides/ --pdf --allow-local-files | ||
| env: | ||
| CHROME_PATH: "" | ||
| PUPPETEER_SKIP_CHROMIUM_DOWNLOAD: "false" | ||
|
|
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| - name: save artifacts | ||
| uses: actions/upload-artifact@v4 | ||
| with: | ||
| name: Coursework-Presentations | ||
| path: slides/*.pdf | ||
| retention-days: 30 |
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| Original file line number | Diff line number | Diff line change |
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| @@ -0,0 +1,3 @@ | ||
| venv | ||
| octave-workspace | ||
| .DS_Store |
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| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC | ||
| export APT_HOME=~/Downloads/APT_v3.1.0 | ||
| export PATH=$PATH:$APT_HOME | ||
| export APT_ARCH=MAC |
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| Original file line number | Diff line number | Diff line change |
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| @@ -0,0 +1,133 @@ | ||
| # Самостоятельная работа: Дискретное преобразование Фурье. Вариант 1 | ||
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| ## Аналитический расчет коэффициентов ряда Фурье | ||
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| $$ | ||
| \left\{ | ||
| \begin{aligned} | ||
| a_0 &= 0.1 \text{ МПа} \\ | ||
| f_0 &= 2 \text{ МГц} \\ | ||
| \omega_0 &= 2\pi f_0 \\ | ||
| p(t) &= 2a_0 \sin(3\omega_0 t) + a_0 \cos(5\omega_0 t) | ||
| \end{aligned} | ||
| \right. | ||
| $$ | ||
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| ### Определение периода $T$ | ||
| Сигнал состоит из двух гармоник с частотами $f_1 = 3f_0 = 6$ МГц и $f_2 = 5f_0 = 10$ МГц. | ||
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| Определим базовую частоту: | ||
| $$ | ||
| f_0 = \text{НОД(6 МГц, 10 МГц)} = \text{2МГц} | ||
| $$ | ||
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| Следовательно, период сигнала $T$ равен: | ||
| $$ | ||
| T = \frac{1}{f_0} = \frac{1}{2 \cdot 10^6} = 0.5 \text{ мкс} | ||
| $$ | ||
|
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| ### Расчет аналитических коэффициентов спектра $p_T(f_n)$ | ||
| Используем формулы Эйлера для представления тригонометрических функций через комплексные экспоненты: | ||
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| $$ | ||
| p(t) = 2a_0 \sin(3\omega_0 t) + a_0 \cos(5\omega_0 t) | ||
| $$ | ||
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| $$ | ||
| \implies | ||
| \left[ | ||
| \begin{aligned} | ||
| \sin(x) = \frac{e^{ix} - e^{-ix}}{2i} = -\frac{i}{2}e^{ix} + \frac{i}{2}e^{-ix} \\ | ||
| \cos(x) = \frac{e^{ix} + e^{-ix}}{2} = \frac{1}{2}e^{ix} + \frac{1}{2}e^{-ix} | ||
| \end{aligned} | ||
| \right] | ||
| $$ | ||
| $$ \implies p(t) = 2(0.1) \left[ -\frac{i}{2}e^{i 3\omega_0 t} + \frac{i}{2}e^{-i 3\omega_0 t} \right] + 0.1 \left[ \frac{1}{2}e^{i 5\omega_0 t} + \frac{1}{2}e^{-i 5\omega_0 t} \right] $$ | ||
| $$ \implies p(t) = -0.1i \cdot e^{i 3\omega_0 t} + 0.1i \cdot e^{-i 3\omega_0 t} + 0.05 \cdot e^{i 5\omega_0 t} + 0.05 \cdot e^{-i 5\omega_0 t} $$ | ||
|
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| Из полученного выражения напрямую следуют аналитические значения комплексных коэффициентов спектра $p_T(f_n)$ на частотах $f_n$: | ||
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| $$ | ||
| \begin{aligned} | ||
| & 3f_0 (6 МГц): p_T(3f_0) = -0.1i & \text{Фаза}& = -\pi/2 \\ | ||
| & -3f_0 (-6 МГц): p_T(-3f_0) = 0.1i; & \text{Фаза}&= \pi/2 \\ | ||
| &5f_0 (10 МГц): p_T(5f_0) = 0.05; & \text{Фаза}& = 0 \\ | ||
| &-5f_0 (-10 МГц): p_T(-5f_0) = 0.05; & \text{Фаза}&= 0\\ | ||
| \end{aligned} | ||
| $$ | ||
|
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| ### Графики функции и аналитического спектра | ||
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| Амплитудный и действительный спектры четные (рис. 1.a, 1.c), а фазовый и мнимый спектры нечетные (рис. 1.b, 1.d). | ||
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|  | ||
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| \newpage | ||
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| ### Код №1 | ||
| ```matlab | ||
| a_0 = 0.1; | ||
| f_0 = 2.0; | ||
| w_0 = 2 * 3.14 * f_0; | ||
| T = 1 / f_0; | ||
| t = 0: 2*T: 1000; | ||
| p_t = 2 * a_0 * sin(3*w_0 * t) + a_0 * cos(5 * w_0 * t); | ||
| freqs_f0_multipliers = -6: 1: 6; | ||
| freqs = freqs_f0_multipliers * f_0; | ||
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| coefficients = zeros(length(freqs), length(t)); | ||
| coefficients(freqs_f0_multipliers == 3) = -0.1i; | ||
| coefficients(freqs_f0_multipliers == -3) = 0.1i; | ||
| coefficients(freqs_f0_multipliers == 5) = 0.05; | ||
| coefficients(freqs_f0_multipliers == -5) = 0.05; | ||
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| c_amp = abs(coefficients); | ||
| c_phase = angle(coefficients); | ||
| c_real = real(coefficients); | ||
| c_im = imag(coefficients); | ||
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| figure('Position', [110, 55, 1200, 1200]); | ||
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| axes('Position', [0.0667, 0.7066, 0.9208, 0.2606]); | ||
| plot(t, p_t); | ||
| title('Исходный акустический сигнал p(t)'); | ||
| xlabel('Время t, мкс'); | ||
| ylabel('p(t), МПа'); | ||
| grid on; | ||
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| axes('Position', [0.08, 0.38, 0.39, 0.22]); | ||
| stem(freqs, c_amp); | ||
| hold on; plot(xlim, [0 0]); hold off; | ||
| title('Амплитудный спектр |p_T(f_n)|'); | ||
| xlabel('Частота f_n, МГц'); | ||
| grid on; | ||
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| axes('Position', [0.57, 0.38, 0.39, 0.22]); | ||
| stem(freqs, c_phase); | ||
| hold on; plot(xlim, [0 0]); hold off; | ||
| title('Фазовый спектр arg(p_T(f_n))') | ||
| xlabel('Частота f_n, МГц'); | ||
| ylabel('Фаза p_T(f_n)'); | ||
| grid on; | ||
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| axes('Position', [0.08, 0.07, 0.39, 0.22]); | ||
| stem(freqs, c_real); | ||
| hold on; plot(xlim, [0 0]); hold off; | ||
| title('Действительная часть спектра Re(p_T(f_n))') | ||
| xlabel('Частота f_n, МГц'); | ||
| grid on; | ||
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| axes('Position', [0.57, 0.07, 0.39, 0.22]); | ||
| stem(freqs, c_im); | ||
| hold on; plot(xlim, [0 0]); hold off; | ||
| title('Мнимая часть спектра Im(p_T(f_n))') | ||
| xlabel('Частота f_n, МГц'); | ||
| grid on; | ||
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| print(gcf, 'fig_1_m.png', '-dpng', '-r300'); | ||
| ``` |
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| ## Выбор параметров дискретизации | ||
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| ### Теорема Котельникова и шаг дискретизации $h$ | ||
| Согласно теореме Котельникова, частота дискретизации $f_s$ должна быть более чем в два раза выше максимальной частоты, присутствующей в спектре сигнала: | ||
| $$ f_s > 2 f_{max} $$ | ||
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| Из результатов аналитического расчета: | ||
| $$ f_{max} = 5f_0 = 10 \text{ МГц} \implies f_s > 20 \text{ МГц} $$ | ||
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| Следовательно, минимально допустимая частота дискретизации: | ||
| $$ f_{s_{min}} = 2 \cdot 10 \text{ МГц} = 20 \text{ МГц} $$ | ||
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| Для шага дискретизации $h$ выберем максимально допустимое значение: | ||
| $$ h < \frac{1}{20 \text{ МГц}} = 0.05 \text{ мкс} $$ | ||
|
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| ### Выбор временного окна $T$ | ||
| Для ДПФ периодического сигнала размер окна должен быть кратным периоду сигнала, поэтому выберем временное окно равным ровно одному периоду сигнала: | ||
| $$ T_{window} = T = 0.5 \text{ мкс} $$ | ||
|
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| ### Определение количества точек $N$ | ||
| Рассчитаем необходимое минимальное количество точек $N^*$ для нашего окна при максимальном шаге дискретизации: | ||
| $$ N^* = \frac{T_{window}}{h_{max}} = \frac{0.5}{0.05} = 10 \text{ точек} $$ | ||
|
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| Чтобы пакетная реализация fft работала эффективно, выберем количество точек как ближайшую степень двойки, превышающую $N^*$: | ||
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| $$ \mathbf{N = 16} $$ | ||
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| ### Итоговые параметры расчетной сетки | ||
| Пересчитаем фактический шаг дискретизации $h$ для выбранного $N$: | ||
| $$ h = \frac{T_{window}}{N} = \frac{0.5}{16} = 0.03125 \text{ мкс} $$ | ||
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| Частота дискретизации при этом составит: | ||
| $$ f_s = \frac{1}{h} = 32 \text{ МГц} $$ |
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