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Integrate a transcendental function of one shifted linear in it, the logarithms of a quotient onto the exponential integral, and derivatives over a power of a logarithm or an inverse - #2034
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…logarithms of a quotient onto the exponential integral, and derivatives over a power of a logarithm or an inverse - A function of one shifted linear c + d x alone with something other than sums, products and powers in it, written in u = c + d x where a power of the linear stands below the bar inside a sum or the linear is written two ways: F^(a + b/(c + d x)^3)/(c + d x)^19, ln(c (d + k/(f + g x)^3)^q). Only for an integrand as written, not one a substitution expands: the inverse sine's of (d + e x^2)^3 (a + b asinh(c x))^2 is a sum of exponentials of linears that cost 370 MB to read. - Powers of two linears beside a negative power of a logarithm of their quotient, onto the exponential integral in that quotient; the zero- discriminant case of SolveAnExponentialOverSeveralLinears no longer divides by the difference of its two equal roots. - The derivative of a function over a power of a logarithm, an inverse trigonometric function or a sum holding a logarithm, whose terms are not elementary apart. - A product of powers whose own logarithmic derivative is a constant, and a power with x in its base and its exponent as an exponential, its free terms raised: x^(-2 - 1/x) (1 - ln(x)) is -(x^(-1/x))'. - The Risch-Norman ansatz with li(x), and erfi beside one Gaussian with a factor of x alone below the bar, in a second pass: e^((a + x)^2)/x^2 - 2 a e^((a + x)^2)/x. Beside a polynomial, or two Gaussians, the pass declined at three times the allocation of the rules after it, and is not taken there. Chain against master 6e16aae: pocket of 1,105 rows, 1,072 -> 1,085 solved, 0 wrong; family 3's sample 222 -> 224, the others unchanged; the 13 rows that moved, alone, 0 -> 13 solved; 6,603 rows compared for allocation, none grew past 1.3x. Part of #233. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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This was referenced Oct 22, 2026
Read a power with x in its base and its exponent as an exponential for the Risch-Norman ansatz
#2044
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Part of #233.
Thirteen of Rubi's exponential, logarithmic and hyperbolic rows that master 6e16aae declines or runs out of time on:
c + d xalone is written inu = c + d x, where a power of the linear stands below the bar inside a sum or the linear is written two ways:F^(a + b/(c + d x)^3)/(c + d x)^19,ln(c (d + k/(f + g x)^3)^q).SolveAnExponentialOverSeveralLinearsno longer divides by the difference of its two equal roots.x^(-2 - 1/x) (1 - ln(x))is-(x^(-1/x))'. Master had since gained its own reading of x-in-both powers, and the rebase merged the two.li(x), anderfibeside one Gaussian, in a second pass.Scopes, found by the first chain's allocation check. Fifteen rows had grown past 1.3x, up to +5.5 GB, with the same answers.
(d + e x^2)^3 (a + b asinh(c x))^2cost 370 MB to read.Chain against master 6e16aae, after the scopes:
The full unit suite passes locally: 16368 passed, 0 failed. The branch is rebased onto 47ab958, and the 13 still answer there. The BREAKING-CHANGES lengths were re-measured, and the v2.5.0 column was measured on a build: four rows that 2.5.0 runs past twenty seconds on now say so.
Rebased onto 2a98be4, after #2030. That entry's two 3.2.1 rows,
1/((a g + b g x)^2 (A + B ln(k (a + b x)/(c + d x)))^2)and its n-th-power twin, are now answered first by this branch's rule onto the exponential integral. They come back in 340 and 394 characters where #2030 wrote 358 and 412, and the commit updates those two rows of its entry.🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura